The correct option is C LiCl<BeCl2<BCl3<CCl4
According to Fajan's rule, as charge on cations increases, their polarising power increases and thus covalent character increases.
Charge on cation increases as follows :
Li+<Be2+<B3+<C4+
So, covalent character increases as:
LiCl<BeCl2<BCl3<CCl4