Which of the following is least hydrolysed?

B e {C l}_{2}

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M g {C l}_{2}

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C a {C l}_{2}

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B a {C l}_{2}

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Solution

The correct option is D $B a {C l}_{2}$
The ability of hydrolysis of halides of particular group decreases down the group. As we move down, the ionization ability of the cation decreases. So, the ability of hydrolysis decreases.
So, in the given halides $B a C l_{2}$ is least hydrolysed as $B a$ is the bottom most element in the group.
Hence, option D is correct.

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Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e {C l}_{2}, M g {C l}_{2}, C a {C l}_{2}

B a {C l}_{2}

B e C l_{2}, S r C l_{2}, M g C l_{2}, C a C l_{2}, B a C l_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B a C l_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

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