Which of the following is not a byproduct of Hoffmann bromamide degradation of acetamide with alcoholic KOH?

K B r

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K C N

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K_{2} C O_{3}

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H_{2} O

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Solution

The correct option is B $K C N$
Acetamide $C H_{3} C O N H_{2}$ reacts with $B r_{2}$ and 4 molecules of $K O H$ to form methylamine (main product) along with 2 molecules $K B r$ , 2 molecules of $H_{2} O$ and one molecule of $K_{2} C O_{3}$ .
$C H_{3} C O N H_{2} B r_{2} + 4 K O H - ------ \to C H_{3} N H_{2} + 2 K B r + K_{2} C O_{3} + 2 H_{2} O$

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