Which of the following is not a possible termination step in the free radical chlorination of methane?

∙ C H_{3} + C l_{2} \to C H_{3} - C l + ∙ C l

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∙ C H_{3} + ∙ C H_{3} \to C H_{3} - C H_{3}

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∙ C H_{3} + ∙ C l \to C H_{3} - C l

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∙ C l + ∙ C l \to C l_{2}

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Solution

The correct option is A $∙ C H_{3} + C l_{2} \to C H_{3} - C l + ∙ C l$
Free radical halogenation reaction follows free radical mechanism.
Any steps that decrease the concentration of radicals are termination steps.
In (a) one $∙ C l$ is produced for every $∙ C H_{3}$ consumed, hence, it is not the termination step.
All others options are consuming radicals, hence, termination steps.

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