Which of the following is not affected by change in pressure?

N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)

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N_{2} (g) + 3 H_{2} (g) \Leftrightarrow 2 N H_{3} (g)

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P C l_{5} (g) \Leftrightarrow P C l_{3} (g) + C l_{2}

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2 S O_{2} (g) + O_{2} (g) \Leftrightarrow 2 S O_{3} (g)

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Solution

The correct option is A $N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)$
For the reaction, $N_{2} (g) + O_{2} (g) \Leftrightarrow 2 N O (g)$ , the value of $Δ n$ is $2 - (1 + 1) = 0$ . When there is no change in the number of moles of reactants and products, there is no effect on the equilibrium when pressure is changed.
In all other option, the number of mole of reactant and products are different,
Hence, if pressure is changed the equilibrium will be affected.

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Similar questions

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

log \frac{K_{p}}{K_{c}} + log R T = 0

log \frac{K_{P}}{K_{C}} + log R T = 0

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

K_{p}

K_{c}

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