Which of the following is NOT equivalent to the molar volume of gas?

44

g of

C O_{2}

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6.022 \times 10^{23}

molecules of

H_{2}

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6.022 \times 10^{23}

atoms of

N

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0.6022 \times 10^{24}

molecules of

O_{2}

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Solution

The correct option is D $6.022 \times 10^{23}$ atoms of $N$
Nitrogen exists in molecular state as $N_{2}$ ,so,two moles of $N$ -atoms will constitute one mole on nitrogen.Therefore, $2 \times (6.022 \times 10^{23})$ will be equivalent to the molar volume of nitrogen $(N_{2})$

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Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

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6.022 \times 10^{23}

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Which of the following is NOT equivalent to the molar volume of gas?

The correct option is D 6.022×1023 atoms of NNitrogen exists in molecular state as N2,so,two moles of N-atoms will constitute one mole on nitrogen.Therefore,2×(6.022×1023) will be equivalent to the molar volume of nitrogen(N2)

The correct option is D $6.022 \times 10^{23}$ atoms of $N$
Nitrogen exists in molecular state as $N_{2}$ ,so,two moles of $N$ -atoms will constitute one mole on nitrogen.Therefore, $2 \times (6.022 \times 10^{23})$ will be equivalent to the molar volume of nitrogen $(N_{2})$