Which of the following is not $s p^{3}$ hybridise

B H_{3}

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B H_{4}^{-}

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N H_{4}^{+}

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N H_{3}

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Solution

The correct option is A $B H_{3}$
$B H_{3} \to S p^{2}$ $N H_{4}^{+} \to S p^{3}$
$B H_{4}^{-} \to S p^{3}$ $N H_{3} \to S p^{3}$

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