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B
Ce4+
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C
Eu2+
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D
Yb2+
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Solution
The correct option is C Eu2+ Lanthanoids exhibit f 0 (Ce4+) and the f 14 (Yb2+ and Lu3+ ) configurations with no unpaired electron, thus, they are diamagnetic, whereas, Eu2+exhibits f7 configuration with seven unpaired electrons.