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Meso Compounds

Which of the ...

Question

Which of the following is responsible for the inability of meso compound to show optical activity?

A

The absence of chiral center

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B

The presence of more than one chiral center

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C

Dissymmetric nature of its structure

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D

Internal compensation

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Solution

The correct option is C Internal compensation
When the upper half of the optical isomer is a mirror image of the lower half then molecule becomes optically inactive due to internal compensation.

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Q. An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral centre is not the sufficient criterion for optical activity. The ultimate criterion is the presence or absence of either plane or centre of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereoisomers of the compounds. Those words are diastereomers and mesomers.

Optically active compounds among the following is :

Q. An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral center is not the sufficient criterion for optical activity. The ultimate criterion is presence or absence of either plane or center of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereoisomers of the compounds. Those words are diastereomers and mesomers.
Optically active compounds among the following is/are
(A)

C H_{3} - C H = C = C H_{2}

C H_{3} - C H = C = C H - C H_{3}

Q. An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral centre is not the sufficient criterion for optical activity. The ultimate criterion is the presence or absence of either plane or centre of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereo isomers of the compounds. Those words are diastereomers and mesomers.
The optical rotation of a solution of pure natural camphor is found to be

+ {5.76}^{o}

under the following conditions: concentration

= 0.13 g / m l

, length of polarimeter

=

1dm, wavelength

=

T = 25^{o}

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