Which of the following is the configuration of silver atom in ground energy state?

[K r] 3 d^{10} 4 s^{1}

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[X e] 4 f^{14} 5 d^{10} 6 s^{1}

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[K r] 4 d^{10} 5 s^{1}

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[K r] 4 d^{9} 5 s^{2}

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Solution

The correct option is B $[K r] 4 d^{10} 5 s^{1}$
Atomic weight of Ag = 47.
E.C of Ag = $[K r] 4 d^{10} 5 s^{1}$ & not $[K r] 4 d^{9} 5 s^{2} .$
This is because fully filled $4 d^{10}$ is more stable than s-subshell.

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Similar questions

The correct ground state configuration of Kr is:

4 d^{10} 5 s^{2} 5 p^{2}

[K r] 4 d^{10}

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