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Oxyacids of Phosphorus

Which of the ...

Question

Which of the following is the conjugate acid of $H P O_{4}^{- 2}$ ?

H_{2} P O_{4}^{-}

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P O_{4}^{- 3}

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H_{3} P O_{4}

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H_{3} O^{+}

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Solution

The correct option is A $H_{2} P O_{4}^{-}$
When a base accepts a proton, the resulting species is its conjugate acid.
Now, when $H P O_{4}^{2 -}$ accepts a proton, it gives $H_{2} P O_{4}^{-}$ .
Hence, $H_{2} P O_{4}^{-}$ is the conjugate acid of $H P O_{4}^{2 -}$

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Similar questions

H_{3} P O_{4} + H_{2} O ⇌ H_{3} O^{+} + H_{2} P O_{4}^{-}; p K_{1} = 2.15

H_{2} P O_{4}^{-} + H_{2} O ⇌ H_{3} O^{+} + H P O_{4}^{- 2}; p K_{2} = 7.20

H e n c e, p H o f 0.01 M N a H_{2} P O_{4} i s

H_{2} P O_{4}^{-}

H_{3} P O_{4} + H_{2} O \to H_{3} O^{+} + H_{2} P O_{4}^{-}

H_{2} P O_{4}^{-} + H_{2} O \to H P O_{4}^{2 -} + H_{3} O^{+}

H_{2} P O_{4}^{-} + O H^{-} \to H_{3} P O_{4} + O^{2 -}

H_{2} P O_{4}^{-}

H_{3} P O_{4}

H P O_{4}^{2 -}

H_{2} O + H_{3} P O_{4} ⇌ H_{3} O^{+} + H_{2} P O_{4}^{-}; p K_{1} = 2.15

H_{2} O + H_{2} P O_{4}^{-} ⇌ H_{3} O^{+} + H P O_{4}^{2 -}; p K_{2} = 7.20

p H

0.01 M N a H_{2} P O_{4}

H_{2} P O_{4}^{-}

H_{3} P O_{4} + H_{2} O \to H_{3} O^{+} + H_{2} P O_{4}^{-}

H_{2} P O_{4}^{-} + H_{2} O \to H P O_{4}^{2 -} + H_{3} O^{+}

H_{2} P O_{4}^{-} + O H^{-} \to H_{3} P O_{4} + O^{2 -}

H_{2} P O_{4}^{-}

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