Which of the following is the correct expression for lower class limit- nbsp-m - class midpoint- u - upper class limit- l - lower class limit-l - m - 2ul - m nbsp-ul - 2m -u nbsp-l - 2m nbsp-u

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Class Size

Which of the ...

Question

Which of the following is the correct expression for lower class limit? ( $m$ = class midpoint, $u$ = upper class limit, $l$ = lower class limit)

l

m

- 2

u

No worries! We‘ve got your back. Try BYJU‘S free classes today!

l

m

u

No worries! We‘ve got your back. Try BYJU‘S free classes today!

l

= 2

m

u

No worries! We‘ve got your back. Try BYJU‘S free classes today!

l

= 2

m

u

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $l$ = 2 $m$ - $u$
The middle value of each data class is called class midpoint.
To find the class midpoint, take the average of the upper and lower class limits.

$C l a s s M i d p o i n t (m)$ = $\frac{U p p e r c l a s s l i m i t (u) + L o w e r c l a s s l i m i t (l)}{2}$
$o r$
$m$ = $\frac{u + l}{2}$
$\Rightarrow$ $l$ = $2 m - u$

Suggest Corrections

Similar questions

Q. Let m be the midpoint and u be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is
(a) 2m − u
(b) 2m + u
(c) m − u
(d) m + u

Choose the correct answer in each of the following questions:
Let m be the midpoint and u be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is
(a) 2m - u
(b) 2m + u
(c) m - u
(d) m + u

Q. Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is

(a) m+

\frac{l + m}{2}

(b) l+

\frac{m + l}{2}

Q. Let m be the mid-point and u be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is __________.

Q. Let L be the lower class boundary of a class in a frequency distribution and m be the midpoint of the class. Which one of the following is the upper class boundary of the class?
(a)

m + \frac{(m + L)}{2}

(b)

L + \frac{m + L}{2}

(c)

2 m - L

(d)

m - 2 L

Join BYJU'S Learning Program

Which of the following is the correct expression for lower class limit? ( m = class midpoint, u = upper class limit, l = lower class limit)

The correct option is D l = 2 m - uThe middle value of each data class is called class midpoint. To find the class midpoint, take the average of the upper and lower class limits. Class Midpoint(m) = Upper class limit(u) + Lower class limit(l)2 or m = u + l2 ⇒ l = 2 m−u

Which of the following is the correct expression for lower class limit? ( $m$ = class midpoint, $u$ = upper class limit, $l$ = lower class limit)