Which of the following is the correct order of stability of the following four distinct conformations of n-butane?
Staggered > Gauche >Partially eclipsed > Fully eclipsed
Correct option is (a).
Staggered > Gauche > Partially eclipsed > Fully eclipsed.
Staggered is the most stable as the two methyl groups are anti to each other. In fully eclipsed form the two methyl groups are syn to each other ( 0o dihedral angle) angle.