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Question

Which of the following is the correct order of stability of the following four distinct conformations of n-butane?


A

Staggered > Gauche >Partially eclipsed > Fully eclipsed

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B

Gauche Staggered > Partially Eclipsed > Fully eclipsed

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C

Staggered > Partially eclipsed > Gauche >Fully eclipsed

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D

Fully eclipsed > Staggered >Partially eclipsed > Gauche

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Solution

The correct option is A

Staggered > Gauche >Partially eclipsed > Fully eclipsed


Correct option is (a).
Staggered > Gauche > Partially eclipsed > Fully eclipsed.

Staggered is the most stable as the two methyl groups are anti to each other. In fully eclipsed form the two methyl groups are syn to each other ( 0o dihedral angle) angle.


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