Which of the following is the correct order of the rate of reaction of $C_{6} H_{6}, C_{6} D_{6}$ and $C_{6} T_{6}$ towards sulphonation?

Same rates of reactions of

C_{6} D_{6}, C_{6} D_{6}

and

C_{6} T_{6}

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C_{6} T_{6} > C_{6} D_{6} > C_{6} H_{6}

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C_{6} H_{6} > C_{6} D_{6} > C_{6} T_{6}

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C_{6} T_{6} > C_{6} D_{6} = C_{6} T_{6}

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Solution

The correct option is C $C_{6} H_{6} > C_{6} D_{6} > C_{6} T_{6}$
The correct order of the rate of reaction of $C_{6} H_{6}, C_{6} D_{6}$ and $C_{6} T_{6}$ towards sulphonation is $C_{6} H_{6} > C_{6} D_{6} > C_{6} T_{6}$ . As the hydrogen atom of benzene is successively substituted with deuterium and tritium, the rate of the electrophilic aromatic substitution decreases.Concentrated sulphuric acid releases a molecule of $S O_{3}$ . The electrolphile attacks the benzene ring to form a sigma complex. The abstraction of $H^{+}$ is the rate determining step. The bond strength increases in the order $C - H < C - D < C - T$ . Hence, the rate of the reaction decreases in the order $C_{6} H_{6} > C_{6} D_{6} > C_{6} T_{6}$ .

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^{6} C_{0} .^{12} C_{6} -^{6} C_{1} .^{11} C_{6} +^{6} C_{2} .^{10} C_{6} +^{6} C_{2} .^{10} C_{6} -^{6} C_{3} .^{9} C_{6} +^{6} C_{4} .^{8} C_{6} -^{6} C_{5} .^{7} C_{6} +^{6} C_{6} .^{6} C_{6}

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