Which of the following is the decreasing order of their dipole moments?

{N H}_{3} > {B F}_{3} > {N F}_{3}

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{N H}_{3} > {N F}_{3} > {B F}_{3}

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{B F}_{3} > {N H}_{3} > {N F}_{3}

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{B F}_{3} > {N F}_{3} > {N H}_{3}

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Solution

The correct option is B ${N H}_{3} > {N F}_{3} > {B F}_{3}$
In $N H_{3}$ all bond moments assists each other and so net moment adds up.
In $N F_{3}$ , moment of low pairs is opposite to that of $N - F .$ So, net dipole moment reduces.
In $B F_{3}$ , the molecule being planer, the moments cancel each other. Thus net moment is $z e r o .$
Hence, the order, $N H_{3} > N F_{3} > B F_{3}$
See the figure.

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