let us assume that cost price be 100 for all cases
A) two successive discounts of 15% each
for this for 1st discount =(15/100 )*100=15
remaining=100-15=85
for second discount =(15/100)*85=12.75
remaining=85-12.75=72.25
B) discount of 30%
cost=(30/100)*100=30
remaining=100-30=70
C) 10% discount followed by a 20% discount
for 10% discount =(10/100)*100=10
remaining=100-10=90
for 20% discount=(20/100)*90=18
remaining=90-18=72
D) 20% discount followed by a 10% discount
for 20% discount =(20/100)*100=20
remaining=100-20=80
for 10% discount=(10/100)*80=8
remaining=80-8=72
so among all the four cases option B has the least cost price(remaining after giving discount) so the customer is most beneficial for option B