Which of the following is the most polar?

C C l_{4}

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C H C l_{3}

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C H_{3} O H

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C H_{3} C l

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Solution

The correct option is C $C H_{3} O H$
The C-O bond in $C H_{3} O H$ is most polar because oxygen has highest electro negativity than chlorine .Higher electro negativity means higher tendency to attract electrons. Hence oxygen has highest electron attracting power compared to chlorine .Therefore methanol is more polar than $C C l_{4}$ , $C H C l_{3}$ and $C H_{3} C l$ .

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Similar questions

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

C C l_{4}

C H_{3} C l

C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

{C H}_{3} C l, {C H}_{2} {C l}_{2}, C H {C l}_{3}, C {C l}_{4}

{C H}_{3} C l > {C H}_{2} {C l}_{2} > C H {C l}_{3} > C {C l}_{4}

C H_{3} C l

C H_{2} C l_{2}

C H C l_{3}

C C l_{4}

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}

C C l_{4}

{C H}_{3} C l

{C H}_{3} O H

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