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Periodic Properties

Which of the ...

Question

Which of the following is the strongest oxidizing agent?

F_{2}

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B r_{2}

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C l_{2}

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I_{2}

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Solution

The correct option is B $F_{2}$
Among halogens, fluorine is the strongest oxidising agent. It has highest value of oxidation potential. It is due to its low heat of dissociation and high heat of hydration which have more than compensated the lower value of electron affinity.

Suggest Corrections

Similar questions

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

Which is a better oxidizing agent cl2 or f2

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

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