Which of the following is true for a isobaric process?

dQ = 0

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dV = 0

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dP = 0

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dT = 0

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Solution

The correct option is C
dP = 0

As you can see the name of the process itself,
Isobaric - Same pressure. Therefore dP = 0.
During an isobaric process the pressure remains constant throughout the change. Therefore d P = 0.

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Δ G > 0

Δ_{t o t a l} S < 0

T Δ S > 0

Δ G < 0

P Δ V

(d P / d V)_{T} = K / V

(d V / d T)_{p} = K

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