Which of the following is true with respect to crystal field splitting in complexes?

△_{0} = △_{t}

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△_{0} = \frac{9}{4} △_{t}

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△_{t} = \frac{9}{4} △_{0}

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△_{t} = \frac{2}{3} △_{0}

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Solution

The correct option is B $△_{0} = \frac{9}{4} △_{t}$
$△_{t} = \frac{4}{9} △_{0} △_{0} = \frac{9}{4} △_{t}$
These results are obtained from geometrical consideration of tetrahedral and octahedral geometry.

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Similar questions

The crystal field splitting energy for octahedral complex $(Δ_{0})$ and tetrahedral complex $(Δ_{t})$ are related as :

Q. Which of the following statement is true for crystal field splitting of tetrahedral complex?

Q. Which of the following statement(s) is/are true for crystal field splitting of tetrahedral complex?

Q. What is meant by crystal field splitting energy ? On the basis of crystal field theory, write the electronic configuration of

d^{4}

in terms of

t_{2 g}

and

e_{g}

in an octahedral field when
(i)

Δ_{0} > P

(ii)

Δ_{0} < P

Arrange the following complex ions in increasing order of crystal field splitting energy $△_{0} .$
$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}, [C r (N H_{3})_{6}]^{3 +}$

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Which of the following is true with respect to crystal field splitting in complexes?

The correct option is B △0=94△t△t=49△0△0=94△tThese results are obtained from geometrical consideration of tetrahedral and octahedral geometry.

The correct option is B $△_{0} = \frac{9}{4} △_{t}$
$△_{t} = \frac{4}{9} △_{0} △_{0} = \frac{9}{4} △_{t}$
These results are obtained from geometrical consideration of tetrahedral and octahedral geometry.