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Resonance

Which of the ...

Question

Which of the following lone-pair indicated is not involved in resonance?
(A) $C H_{2} = C H - . . N H - C H_{3}$
(B) $C H_{2} = C H - . . O . . - C H_{3}$
(C) $C H_{2} = C H - . . O . . - C H = C H_{2}$
(D) $C H_{2} = C H - N H_{2}$

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Solution

For resonance, there should be alternate lone pair as well as $π -$ bond / or $(σ - / π -)$ alternate.

While compound A,B,C and D there is lone pair and double bond in conjugation so lone pair involve in resonnace.

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Similar questions

C H_{2} = C H - + C H_{2} and C H_{2} = C H - C H_{2} - + C H_{2}

C H_{3} - N H - + C H_{2} and + C H_{2} - O H

C H_{3} - O - C H_{2} - + C H_{2} and C H_{2} - O - + C H_{2}

C H_{3} - + C H - C H_{2} C H_{2} C H_{3} and C H_{3} C H_{2} - + C H - C H_{2} C H_{3}

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

A g N O_{3}

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

I . ⊖ C H_{2} - \oplus C H - C H = C H - O - C H_{3}

I I . ⊖ C H_{2} - C H = C H - \oplus C H - O - C H_{3}

I I I . C H_{2} = C H - ⊖ C H - \oplus C H - O - C H_{3}

I V . C H_{2} = C H - ⊖ C H - C H = \oplus O - C H_{3}

C H_{2} = C H - C H = C H - O - C H_{3}

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