Which of the following molecular formula does not show chain isomerism?

C_{4} H_{10}

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C_{4} H_{8}

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C_{4} H_{6}

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C_{4} H_{8} O

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Solution

The correct option is D $C_{4} H_{6}$
In chain isomerism, or skeletal isomerism, components of the skeleton are distinctly re-ordered to create different structures.

Butane $C_{4} H_{10}$ , Butene $C_{4} H_{8}$ and Butanal $C_{4} H_{8} O$ shows chain isomerism but 1,3-Butadiene $C_{4} H_{6}$ can not be re-ordered to create chain isomer.

Option C is correct.

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C_{4} H_{8}

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(C_{9} H_{8} O_{4})

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(C_{4} H_{6} O_{3})

C_{7} H_{6} O_{3} + C_{4} H_{6} O_{3} \to C_{9} H_{8} O_{4} + C_{2} H_{4} O_{2}

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