The correct option is A NCl3
→NCl3+3H2O→NH3+HOCl
→PCl3+3H2O→H3PO3+3HCl
→AsCl3+H2O→As(OH)3+3HCl
→SbCl3+H2O→SbOCl+2HCl
In the case of NCl3, the water attacks the vacant d orbitals of Cl whereas in the others, attack occurs at the central atom. Hence in those cases it forms HCl.