The correct option is A O(SiH3)2
a) In O(SiH3)2, oxygen has a lone pair in p-orbital and Si has vacant d-orbitals. So, O(SiH3)2 has 2pπ−3dπ back bonding.
b) In OI2 oxygen has a lone pair in p-orbital and I have a vacant 5d-orbital. Hence,due to large size difference it has poor overlapping as compared to O(SiH3)2.
c) In NCl3 there is no back bonding due to less electronegativity difference of Nitrogen and Chlorine.
Hence, O(SiH3)2 has the maximum extent of overlapping.