Question

Which of the following molecules have the same hybridisation?
$\left(i\right)PC{l}_3\left(ii\right)H_{2}O\left(iii\right)C{O}_2\left(iv\right)N{H}_3\left(v\right)S{O}_4^{2-}\left(vi\right)N{O}_3^{-}$

• A. $\left(i\right)$ and $\left(ii\right)$
• B. $\left(i\right),\left(ii\right),\left(iii\right),\left(iv\right)$ and $\left(v\right)$
• C. $\left(i\right),\left(iii\right),\left(v\right)$ and $\left(vi\right)$
• D. $\left(i\right),\left(ii\right),\left(iv\right)$ and $\left(v\right)$

Answer 1

The correct option is D $\left(i\right),\left(ii\right),\left(iv\right)$ and $\left(v\right)$

(i) $PC{l}_3\to$ $P$ has three sigma bonds and one lone pair. So, the steric number is 4. Therefore, it is $s{p}^3$ hybridised.


(ii) $H_{2}O\to$, $O$ has two sigma bonds and two lone pairs. Thus, the steric number is 4. Therefore, it is $s{p}^3$ hybridised.


(iii) $C{O}_2\to$ $C$ has two sigma bonds and has no lone pairs. Thus, the steric number is 2. Therefore, it is $sp$ hybridised.



(iv) $N{H}_3\to$ $N$ has three sigma bonds and one lone pair. Thus, the steric number is 4. Therefore, it is $s{p}^3$ hybridised.



(v) $S{O}_4^{2-}\to$ $S$ has four sigma bonds and there is no lone pair of electrons. Thus, the steric number is 4. Therefore, it is $s{p}^3$ hybridised.



(vi) $N{O}_3^{-}\to$ $N$ has three sigma bonds and there is no lone pair of electrons. So, the steric number is 3 and is $s{p}^2$ hybridised.