Which of the following molecules represents the order of hybridisation $s p^{2}, s p^{2}, s p, s p$ from left to right carbon atoms?

C H_{2} = C H - C H = C H_{2}

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H C = C - C \equiv C H

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C H_{3} - C H = C H - C H_{3}

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C H_{2} = C H - C \equiv C H

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Solution

The correct option is B $C H_{2} = C H - C \equiv C H$
$C H_{2} = C H - C \equiv C H$ represents the order of hybridization $s p^{2}, s p^{2}, s p, s p$ from left to right atoms. C atoms attached to a double bond are $s p^{2}$ hybridized. C atoms attached to a triple bond are $s p$ hybridized.

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Similar questions

Q. Which of the following molecules represents the order of hybridisation

s p^{2}

s p^{2}

s p

s p

from left to right?

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

C_{2}

and

C_{3}

atoms in

C H \equiv C - C H = C H_{2}

are respectively

s p

and

s p^{2}

hybridised.

Q. Which of the following has a bond formed by overlap of

s p - s p^{3}

hybrid orbitals

Q. In the compound

C H_{3} - C H = C H - C H_{2} - C \equiv C H

, the hybridisation of C₁, C₃ and C₅ bonds respectively is

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Which of the following molecules represents the order of hybridisation sp2,sp2,sp,sp from left to right carbon atoms?

The correct option is B CH2=CH−C≡CHCH2=CH−C≡CH represents the order of hybridization sp2,sp2,sp,sp from left to right atoms. C atoms attached to a double bond are sp2 hybridized. C atoms attached to a triple bond are sp hybridized.

Which of the following molecules represents the order of hybridisation $s p^{2}, s p^{2}, s p, s p$ from left to right carbon atoms?

The correct option is B $C H_{2} = C H - C \equiv C H$
$C H_{2} = C H - C \equiv C H$ represents the order of hybridization $s p^{2}, s p^{2}, s p, s p$ from left to right atoms. C atoms attached to a double bond are $s p^{2}$ hybridized. C atoms attached to a triple bond are $s p$ hybridized.