Which of the following numbers exceeds 9999999 by 1?

10000000

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1000000

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10000

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9999998

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Solution

The correct option is A
10000000

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Similar questions

\frac{1}{3}

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Question 97

Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.

The value of `n' for which the number of diagonals that can be drawn in a
polygon exceeds the number of side by 1 is -

\frac{2}{5}

\frac{1}{7}

36

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