Which of the following options correctly match, when subject of the formula is change to x.

$y = \frac{3 x^{2} + 4}{x^{2} - 5}$

√{(5y + 4)/ (y – 3)}

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√{(5y - 4)/ (y + 3)}

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√{(5y - 4)/ (y – 3)}

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√{(4y + 5)/ (y +3)}

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Solution

The correct option is A
√{(5y + 4)/ (y – 3)}

$y = \frac{3 x^{2} + 4}{x^{-} 5} y (x^{2} - 5) = (3 x^{2} + 4) x^{2} (y - 3) = (5 y + 4) x^{2} = \frac{5 y + 4}{y - 3} x = \sqrt{\frac{5 y + 4}{y - 3}}$

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Similar questions

2 y^{2} - 4 y - 30

6 y^{5} - y^{4} + 4 y^{3} - 5 y^{2} - y - 15

y = 3

\frac{5 y - 4}{8} - \frac{y - 3}{5} = \frac{y + 6}{4}

\frac{5 y - 4}{8} - \frac{y - 3}{5} = \frac{y + 6}{4}

\frac{3 x + 4 y}{2 x + 5 y} = \frac{4}{3}

9 x + 12 y = 8 x + 20 y

\frac{3 x + 4 y}{2 x + 5 y} = \frac{4}{3}

\frac{x}{y} = 8 \Rightarrow x : y = 8 : 1

3 (3 x + 4 y) = 4 (2 x + 5 y)

x = 8 y

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