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Question

Which of the following orbital has most energy in multi-electron system?


A

3s

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B

4p

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C

4d

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D

4s

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Solution

The correct option is C

4d


Try to use Bohr - Bury rule of (n + l) here.

Whichever is having more value of (n + l) value will have more energy.

3s 3 + 0 = 3

4p 4 + 1 = 5

3d 3 + 2 = 5

4s 4 + 0 = 4

Now, between 3d and 4p, because they have same (n + l) value, whichever orbitals 'n' is greater, will have more energy.

So, 4p will have most energy.


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