Question

Which of the following orbitals does not exist according to quantum theory?

• A. $5g$
• B. $4f$
• C. $5h$
• D. $6h$

Answer 1

The correct option is C $5h$

Orbital	Value of l
s	$0$
p	$1$
d	$2$
f	$3$
g	$4$
h	$5$

For $5g$,
Principal quantum number $n=5$
We know that, Azimuthal quantum number $l$ ranges from $0$ to $n-1$
$\because l<n,$ hence it exists.

For $4f$,
$n=4$
$l=3$ for f orbital
$\because l<n,$ hence it exists.

For $5h$,
$n=5$ and l ranges from 0 to n - 1
$h$ subshell has $l=5$ which is not possible

For $6h$,
$n=6$
For h subshell, l = 5
$\because l<n,$ hence it exists.