Question

Which of the following pair of molecules has same shape?

• A. $C{F}_4,S{F}_4$
• B. $Xe{F}_2,C{O}_2$
• C. $B{F}_3,PC{l}_3$
• D. $P{F}_5,I{F}_5$

Answer 1

The correct option is B $Xe{F}_2,C{O}_2$

(a) $C{F}_4\Rightarrow$ Hybridisation : $s{p}^3$
geometry : tetrahedral
shape : tetrahedral
$S{F}_4\Rightarrow$ Hybridisation = $s{p}^{3}d$
geometry = trigonal bipyramidal
shape = see saw

(b) $Xe{F}_2\Rightarrow$ Hybridsation $=s{p}^{3}d$
geometry = trigonal bipyramidal
shape = linear
$C{O}_2=$ linear $\Rightarrow$ shape
$O=C=O$

(c) $B{F}_3\Rightarrow$ hybridisation = $s{p}_2$
geometry = trigonal planar
shape = trigonal planar
$PC{l}_3\Rightarrow$ Hybridisation = $s{p}^3$
Geometry $\Rightarrow$ tetrahedral
shape $\Rightarrow$ pyramidal

(d) $P{F}_5,I{F}_5$
$P{F}_5\Rightarrow$ Hybridisation = $s{p}^{3}d$
Geometry $\Rightarrow$ trigonal bipyramidal
shape $\Rightarrow$ trigonal bipyramidal
$I{F}_5=$ Hybridisation = $s{p}^3{d}^2$
Geometry = Octahedral
Shape = Square Pyramidal

Hence, option (b) is correct.