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Solubility

Which of the ...

Question

Which of the following pairs of cations can be separated by using an $N H_{3}$ solution?

C u^{2 +}, A g^{+}

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P b^{2 +}, A g^{+}

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A g^{+}, Z n^{2 +}

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C u^{2 +}, C d^{2 +}

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Solution

The correct option is D $P b^{2 +}, A g^{+}$
With ammonia solution, $P b^{2 +}$ gives a white ppt. of lead hydroxide.
$P b^{2 +} + 2 N H_{4} O H ⟶ P b (O H)_{2} W h i t e p p t . + 2 N H_{4}^{+}$

But $[A g ({N H}_{3})_{2}]^{+} S o l u b l e$ + $C l^{-}$

The correct answer is $P b^{2 +}, A g^{+}$ as one forms ppt. and other forms soluble complex.

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Similar questions

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

C u | C u^{2 +} (1 M) | | A g^{+} (1 M) | A g, E^{o} = 0.46 V

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u, E^{o} = 1.10 V

Z n | Z n^{2 +} | | A g^{+} (1 M) | A g

C u | C u^{2 +} (1 M) | | A g^{+} (1 M) | A g, E^{0} = 0.46 V

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u, E^{0} = 1.10 V

Z n | Z n^{2 +} (1 M) | | A g^{+} (1 M) | A g

298 K

C u (s) | C u^{2 +} (1.0 M) | | A g^{+} (1.0 M) | A g (s)

E_{c e l l}^{o} = 0.46 V

Z n (s) | Z n^{2 +} (1.0 M) | | C u^{2 +} (1.0 M) | C u (s)

E_{c e l l}^{o} = 1.10 V

E_{c e l l}

298 K

Z n (s) | Z n^{2 +} (0.1 M) | | A g^{+} (1. 0 M) | A g (s)

(E^{\circ})

A g / A g^{+} (1 M) ∥ C u^{2 +} (1 M) | C u; E^{\circ} = - 0.46 v o l t

Z n / Z n^{2 +} (1 M) ∥ C u^{2 +} (1 M) | C u; E^{\circ} = + 1.10 v o l t

Z n | Z n^{2 +} (1 M) ∥ A g^{+} (1 M) | A g

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