Which of the following pairs of ions contain the same number of unpaired electrons?

N i^{2 +}, C o^{2 +}

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M n^{2 +}, F e^{3 +}

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M n^{2 +}, N i^{2 +}

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T i^{3 +}, C o^{2 +}

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Solution

The correct option is A $M n^{2 +}, F e^{3 +}$
Goal:- Electronic configuration
$F e^{3 +}$ : 5 unpaired $[A r] 3 d^{5}$
$M n^{2 +}$ : 5 unpaired $[A r] 3 d^{5}$
$N i^{2 +}$ : 2 unpaired $[A r] 3 d^{8}$
$C o^{2 +}$ : 3 unpaired $[A r] 3 d^{7}$
$T i^{3 +}$ : 1 unpaired $[A r] 3 d^{1}$

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Write down the number of 3d electrons in each of the following ions:

Ti²⁺, V²⁺, Cr³⁺, Mn²⁺, Fe²⁺, Fe³⁺, CO²⁺, Ni²⁺ and Cu²⁺.

Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

M n^{2 +}, C o^{2 +}, Z n^{2 +} & N i^{2 +}

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