Question

Which of the following particles will experience a maximum magnetic force when projected with the same velocity perpendicular to a magnetic field?

• A. Electron
• B. Proton
• C. ${\mathrm{He}}^{+}$
• D. ${\mathrm{Li}}^{++}$

Answer 1

The correct option is D

${\mathrm{Li}}^{++}$

Explanation

We know, magnetic force,

$\overrightarrow{F}=q\left(\overrightarrow{v}\times \overrightarrow{B}\right)$

Given, that velocity and magnetic field are the same for all four options.

So, the particle with maximum charge will have a maximum magnetic force.

Explanation of correct option

Option D,

${\mathrm{Li}}^{++}$ has two $+ve$ charges.

Since ${\mathrm{Li}}^{++}$ has more charge, the magnetic force is maximum for ${\mathrm{Li}}^{++}$.

Option D is correct.

Explanation of incorrect options

Option A,

The electron has one $-ve$ charge.

Option B,

Proton has one $+ve$charge.

Option C,

${\mathrm{He}}^{+}$ has one $+ve$ charge.

Option A, B and C are incorrect.

Thus, option D is correct.