Which of the following plots does not represent Boyle’s law?
A
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B
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C
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D
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Solution
The correct option is C From Boyle’s Law, PV=Constant P=KV
Taking log on both side, we get: logP=logK−logV logP=logK+logV−1---(i)
On comparing equation (i) with the equation of a straight line i.e y = c + mx,
We get the slope for the graph between log P and log V−1 is +1.
Whereas, for option (c), slope=tan135∘=−1
So, option (c) is does not represent Boyle's law.
The different graphical representations of Boyle’s Law are: