Which of the following presents the correct order of the acidity in the given compounds?

$F C H_{2} C O O H > C l C H_{2} C O O H > B r C H_{2} C O O H > C H_{3} C O O H$

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$C H_{3} C O O H > B r C H_{2} C O O H > C l C H_{2} C O O H > F C H_{2} C O O H$

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$F C H_{2} C O O H > C H_{3} C O O H > B r C H_{2} C O O H > C l C H_{2} C O O H$

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$B r C H_{2} C O O H > C l C H_{2} C O O H > F C H_{2} C O O H > C H_{3} C O O H$

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Solution

The correct option is A
$F C H_{2} C O O H > C l C H_{2} C O O H > B r C H_{2} C O O H > C H_{3} C O O H$

Acetic acid is the least acidic because there are no electronegative substituents at the $α$ position. The presence of such an electronegative substituent tends to stabilize the negative charge present in the conjugate base of the given acids (via -I effect). Hence the increasing order of acidic strength is:

$F C H_{2} C O O H > C l C H_{2} C O O H > B r C H_{2} C O O H > C H_{3} C O O H$

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Similar questions

p K_{a}

C F_{3} C O O H, C C l_{3} C O O H, H C C l_{2} C O O H, N O_{2} C H_{2} C O O H, F C H_{2} C O O H, C l C H_{2} C O O H, B r C H_{2} C O O H, H C O O H, C l C H_{2} C H_{2} C O O H, C_{6} H_{5} C O O H, C_{6} H_{5} C H_{2} C O O H, C H_{3} C O O H, C H_{3} C H_{2} C O O H

{C l}_{3} C C O O H > {C l}_{2} C H C O O H > C l {C H}_{2} C O O H

{C H}_{3} C H_{2} C O O H > {(C H}_{3})_{2} C H C O O H > {(C H}_{3})_{3} C C O O H

F_{2} C H_{2} C O O H > F C H_{2} C O O H > C l {C H}_{2} C O O H

C l_{3} C C O O H > C l_{2} C H C O O H > C l C H_{2} C O O H

C l_{3} C C O O H > C l_{2} C H C O O H > C l C H_{2} C O O H

C H_{3} C H_{2} C O O H > (C H_{3})_{2} C H C O O H > (C H_{3})_{3} C . C O O H

$C H_{3} C O C H_{2} C l O H^{-}, C l_{2} - ---- \to$ Product P is

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