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Acid Rain

Which of the ...

Question

Which of the following reaction is not correct during the formation of acid rain?

A

S + O_{2} \to {S O}_{2}

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B

H_{2} O + {S O}_{2} \to H_{2} {S O}_{3}

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C

H_{2} O + {S O}_{2} \to H_{2} {S O}_{4}

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D

2 {S O}_{2} + O_{2} \to 2 {S O}_{3}

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Solution

The correct option is B $H_{2} O + {S O}_{2} \to H_{2} {S O}_{4}$
$H_{2} O + {S O}_{2} \to H_{2} {S O}_{4}$ is the incorrect.
$H_{2} O + {S O}_{3} \to H_{2} {S O}_{4}$ is the correct reaction.

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Similar questions

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

The heat of formation of

H_{2} {S O}_{4}

S + O_{2} \to {S O}_{2}; △ H = - 298.2 k J

{S 0}_{2} + 1 / 20_{2} \to {S O}_{3}; △ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J

H_{2} + 1 / 20_{2} \to H_{2} O; △ H = - 287 k J

Then the enthalpy of formation of

H_{2} {S O}_{4}

S + O_{2} \to S O_{2}; Δ H = - 398.2 k J; S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{2} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J; H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298

S + O_{2} ⟶ S O_{2}

Δ H = - 398.2 k J

S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3}

Δ H = - 98.7 k J

S O_{3} + H_{2} O ⟶ H_{2} S O_{4}

Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O

Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298 K

S + O_{2} \to {S O}_{2}; △ H = - 398.2 k J : {S O}_{2} + \frac{1}{2} O_{2} \to {S O}_{3}; △ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; △ H = - 130.2 k J : H_{2} + \frac{1}{2} O_{2} \to H_{2} O, △ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at 298 K will be:

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