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Electrochemical Cells, Galvanic Cells

Which of the ...

Question

Which of the following reaction is possible?

I_{2} + 2 N a B r \to 2 N a I + B r_{2}

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I_{2} + 2 N a C 1 \to N a I C 1_{2}

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B r_{2} + 2 N a C l \to 2 N a B r + {C l}_{2}

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{C l}_{2} + 2 N a B r \to 2 N a C l + B r_{2}

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Solution

The correct option is B ${C l}_{2} + 2 N a B r \to 2 N a C l + B r_{2}$
$B r^{-}$ can reduce $C l_{2} t o C l^{-}$ Therefore
$C l_{2} + 2 N a B r \to 2 N a c l \to B r i s p o s s i b l e$
Ecell will be + ve
$∴$ Reaction possible
Here chlorine is displacing bromine from the NaBr because the electronegativity of Cl is more than Br.

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Similar questions

C l_{2} + 2 N a B r \to B r_{2} + 2 N a C l

2 N a + O_{2} \to N a_{2} O

2 K + 2 H_{2} O \to H_{2} + 2 K O H

2 N a B r + C l_{2} \to 2 N a C l + B r_{2}

Δ H^{o}

2 N a B r + C l_{2} = 2 N a C l + {B r}_{2}

Δ H^{o}

Δ H^{o} (N a B r) = - 361 K J / m o l

Δ H^{o} (N a C l) = - 411 K J / m o l

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

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