Which of the following reaction will give 2-pentanone as a significant product?

C H_{3} C H_{2} C H_{2} C \equiv C H + H_{2} S O_{4} (a q) H g S O_{4} - --- \to

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C H_{3} C H_{2} C \equiv C C H_{3} + H_{2} S O_{4} (a q) H_{2} S O_{4} - --- \to

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C H_{3} - C H = C = C H - C H_{3} + H_{2} S O_{4} (a q) H g S O_{4} - --- \to

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C H_{3} C H_{2} - C H = C = C H_{2} + B_{2} H_{6} H_{2} O_{2} - --- \to N a O H

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Solution

The correct options are
A $C H_{3} C H_{2} C H_{2} C \equiv C H + H_{2} S O_{4} (a q) H g S O_{4} - --- \to$
B $C H_{3} C H_{2} C \equiv C C H_{3} + H_{2} S O_{4} (a q) H_{2} S O_{4} - --- \to$
D $C H_{3} C H_{2} - C H = C = C H_{2} + B_{2} H_{6} H_{2} O_{2} - --- \to N a O H$
So, A, B and D are the correct options.

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