Which of the following reagents are used for the detection of acetate and oxalate ions respectively?

B a C l_{2}

and

C a C l_{2}

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N a O H

and

B a C l_{2}

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F e C l_{3}

and

C a C l_{2}

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F e C l_{3}

and

N a O H

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Solution

The correct option is A $F e C l_{3}$ and $C a C l_{2}$
With $F e C l_{3}$ solution. acetates give a deep red colouration due to the formation of ferric acetate.
$3 C H_{3} C O O N a + F e C l_{3} o n b o i l i n g ⟶ [F e (O H)_{2} (C H_{3} C O O)] + 3 N a C I B l o o d r e d c o l o u r a t i o n$
With calcium chloride solution a white crystaline precipitate of calcium oxalate from neutral solutions
is obtained, which is insoluble in dilute acetic acid and oxalic acid but soluble dilute hydrochloric
acid and in dilute nitric acid.
$(C_{2} O_{4})^{2 -} + C a^{2 +} ⟶ C a C_{2} O_{4} W H I T E P P T$

Suggest Corrections

Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e {C l}_{2}, M g {C l}_{2}, C a {C l}_{2}

B a {C l}_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B a C l_{2}

l_{2} / N a O H

{F e C l}_{3}

F e C l_{3} + N a O H \to

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