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Faraday's Second Law

Which of the ...

Question

Which of the following relation is correct according to second low of faraday? Where $m_{1}$ and $m_{2}$ are masses of products and $E_{1}$ and $E_{2}$ are equivalent masses of same products respectively.

A

m_{1} E_{2} = m_{2} E_{1}

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B

m_{1} E_{1} = m_{2} E_{2}

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C

m_{1} + m_{2} = E_{1} + E_{2}

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D

E_{1} E_{2} = m_{1} m_{2}

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Solution

The correct option is A $m_{1} E_{2} = m_{2} E_{1}$
According to Second law of electrolysis of Faraday
The mass of a substance deposited or liberated at any electrode on passing a certain amount of charge is directly proportional to its chemical equivalent weight.
$m α E$
Where m is the mass and E is the equivalent weight
$m_{1} \propto E_{1}$
$m_{1} = K E_{1}$
$m_{2} \propto E_{2}$
$m_{2} = K E_{2}$
$\frac{m_{1}}{m_{2}} = \frac{K E_{1}}{K E_{2}}$
$m_{1} E_{2} = m_{2} E_{1}$

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