Which of the following relation is incorrect?

Δ S = Δ H

T Δ G

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Δ S = \frac{Δ H - Δ G}{T}

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- Δ G = - W_{n o n e x p .}

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W_{P V} = - P Δ V

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Solution

The correct option is A $Δ S = Δ H$ + $T Δ G$
$Δ G = Δ H - T Δ S$
$∴ Δ S = \frac{Δ H - Δ G}{T}$
$Δ G = - W_{n o n e x p .}$
Gibbs free energy is equal to useful work for a spontaneous process
$P - V$ work $= - P Δ V$

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Δ H

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Δ G = Δ H - T Δ S

Δ G = Δ H - T Δ S

Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}

H_{2} (g) + B r_{2} (g) ⟶ 2 H B r (g); Δ H^{⊖} = - 72.40 k J

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