Question

Which of the following represents the anode half cell reaction of a Daniel cell?

• A. $Cu\left(s\right)\to C{u}^{2+}\left(aq\right)+2e^{-}$
• B. $C{u}^{2+}\left(aq\right)+2e^{-}\to Cu\left(s\right)$
• C. $Zn\left(s\right)\to Z{n}^{2+}\left(aq\right)+2e^{-}$
• D. $Z{n}^{2+}\left(aq\right)+2e^{-}\to Zn\left(s\right)$

Answer 1

The correct option is C $Zn\left(s\right)\to Z{n}^{2+}\left(aq\right)+2e^{-}$

One of the most popular galvanic cell is the Daniel cell. Spontaneous redox reaction is used here to produce electricity.
The redox reaction occur in Daniell cell is
$Zn\left(s\right)+C{u}^{2+}\left(aq\right)\to Z{n}^{2+}\left(aq\right)+Cu\left(s\right)$

Anode half cell is zinc rod in zinc sulphate solution.
Anodic half cell reaction is
$Zn\left(s\right)\to Z{n}^{2+}\left(aq\right)+2e^{-}$

Cathode half cell is copper rod in copper sulphate solution.
Cathodic half cell reaction is
$C{u}^{2+}\left(aq\right)+2e^{-}\to Cu\left(s\right)$

Thus, option (c) is correct.