Which of the following represents the correct order of decreasing number of $S = O$ bonds?

H_{2} S O_{4} > H_{2} S O_{3} > H_{2} S_{2} O_{8}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S_{2} O_{8} > H_{2} S O_{3} > H_{2} S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S_{2} O_{8} > H_{2} S O_{4} > H_{2} S O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} S O_{3} > H_{2} S_{2} O_{8} > H_{2} S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $H_{2} S_{2} O_{8} > H_{2} S O_{4} > H_{2} S O_{3}$
The following represents the correct order of decreasing number of $S = O$ bonds.
$H_{2} S_{2} O_{8} > H_{2} S O_{4} > H_{2} S O_{3}$
The number of $S = O$ bonds present in $H_{2} S_{2} O_{8}, H_{2} S O_{4} and H_{2} S O_{3}$ are 4, 2 and 1 respectively.

Suggest Corrections

Similar questions

H_{2} S O_{3}, H_{2} S_{2} O_{8}, H_{3} P O_{2}, H_{3} P O_{5}, H C l O_{2}

H_{2} S O_{3}, H_{2} S O_{4}

H_{2} S_{2} O_{7}

F e_{2} (S O_{4})_{3} + H_{2} S O_{3} + H_{2} O \to F e S O_{4} + H_{2} S O_{4}

H_{2} S, H_{2} S O_{4}, H_{2} S O_{3}, H_{2} S_{2} O_{3}

H_{3} B O_{3}, H_{3} P O_{4}, H_{2} S O_{4}, H_{2} S O_{3}

Join BYJU'S Learning Program