Which of the following represents the given mode of hybridization $s p^{2} - s p^{2} - s p - s p$ from left to right?

C H_{2} = C H - C \equiv N

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C H_{2} = C = C = C H_{2}

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C H_{2} = C H - C H = C H_{2}

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C H_{2} = C = C H - C H_{3}

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Solution

The correct option is A $C H_{2} = C H - C \equiv N$
The type of hybridization of carbon atom is :
(A) $s p^{2} C H_{2}$ = $s p^{2} C H$ - $s p C H$ = $s p N$
(B) $s p^{2} C H_{2}$ = $s p C H$ = $s p C H$ = $s p^{2} C H_{2}$
(C) $s p^{2} C H_{2}$ = $s p^{2} C H$ - $s p^{2} C H$ = $s p^{2} C H_{2}$
(D) $s p^{2} C H_{2}$ = $s p C H$ = $s p^{2} C H$ - $s p^{3} C H_{3}$
Therefore, (A) has the given mode of hybridization from left to right.

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