Question

Which of the following represents the given sequence of hybridisation of carbon atoms from left to right : ${sp}^2,{sp}^2,sp,sp$?

• A. $H_{2}C=CH-C\equiv CH$
• B. $HC\equiv C-CH={CH}_2$
• C. $H_{3}C-CH=CH-C{H}_3$
• D. $H_{2}C=CH-CH={CH}_2$

Answer 1

Answer: (A)

$H_{2}C=CH-C\equiv CH$

Answer:-

$H_2{C}^{{sp}^2}=C^{{sp}^2}H-C^{sp}\equiv C^{sp}H$

First and second carbon atoms are $s{p}^2$ hybridised because it contains 3$\sigma$ bonds and 1$\pi$ bond.

Third and Fourth carbon atoms are $sp$ hybridised because it contains 2$\sigma$ bonds and 2$\pi$ bonds.