Which of the following set of quantum numbers is impossible for an electron?

n = 1, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

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n = 9, l = 7, m_{l} = - 6, m_{s} = - \frac{1}{2}

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n = 2, l = 1, m_{l} = 0, m_{s} = + \frac{1}{2}

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n = 3, l = 2, m_{l} = - 3, m_{s} = + \frac{1}{2}

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Solution

The correct option is D $n = 3, l = 2, m_{l} = - 3, m_{s} = + \frac{1}{2}$
We know that:
$n = 1, 2, . . \infty$
$l = n - 1$
Value of $m_{l} = - l t o + l$
$m_{s} = + \frac{1}{2} o r + \frac{1}{2}$
So option D is not possible.

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