Question

Which of the following should be most volatile?
(I) $C{H}_{3}C{H}_{2}C{H}_{2}N{H}_2$
(II) $(C{H}_3{)}_{3}N$
(III) Ref. image
(IV) $C{H}_{3}C{H}_{2}C{H}_3$

• A. II
• B. IV
• C. I
• D. III

Answer 1

The correct option is B IV

The order of boiling points of isomeric amines is $1^0$ amine > $2^0$ amines > $3^0$ amines.

Because of absence of $H-$atom available for hydrogen bonding, $3^0$ amines do not have intermolecular association.

Intermolecular association is more than $1^0$ amines than in $2^0$ amines as there are two $H$ are also available for $H$ bonding. Hydrocarbons are almost non-polar molecules and possess weak van der Waals forces and hence has lowest boiling point i.e most volatile.