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Question

Which of the following solutions is isotonic with 0.3 N Al2(SO4)3 (100% soluble) solution at given temperature?

A
0.25 M Ca(NO3)2
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B
0.3 N Al(NO3)3
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C
0.15 M KCl
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D
0.25 M glucose
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Solution

The correct option is D 0.25 M glucose
For 0.3 N Al2(SO4)3 solution, =CiRT=0.36×5×RT=0.25RT (i=5)
For 0.25 M Ca(NO3)2 solution, =CiRT=0.25×3×RT=0.75RT (i=3)
For 0.3 N Al(NO3)3 solution, =CiRT=0.33×4×RT=0.4RT (i=4)
For 0.15 M KCl solution, =CiRT=0.15×2×RT=0.3RT (i=2)
For 0.25 M glucose solution, =CiRT=0.25×1×RT=0.25RT (i=1)

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