Question

Which of the following solutions is isotonic with $0.3NA{l}_2(S{O}_4{)}_3$ ($100\%$ soluble) solution at given temperature?

• A. $0.25MCa(N{O}_3{)}_2$
• B. $0.3NAl(N{O}_3{)}_3$
• C. $0.15MKCl$
• D. $0.25Mglucose$

Answer 1

The correct option is D $0.25Mglucose$

For $0.3NA{l}_2(S{O}_4{)}_3$ solution, $\prod =CiRT=\frac{0.3}{6}\times 5\times RT=0.25RT(i=5)$
For $0.25MCa(N{O}_3{)}_2$ solution, $\prod =CiRT=0.25\times 3\times RT=0.75RT(i=3)$
For $0.3NAl(N{O}_3{)}_3$ solution, $\prod =CiRT=\frac{0.3}{3}\times 4\times RT=0.4RT(i=4)$
For $0.15MKCl$ solution, $\prod =CiRT=0.15\times 2\times RT=0.3RT(i=2)$
For $0.25M$ glucose solution, $\prod =CiRT=0.25\times 1\times RT=0.25RT(i=1)$